Alphabeta Math
False statementConstruction: Literature-sourcedVerification: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-05
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FALSE: the Vitali covering theorem holds for arbitrary covers

Statement

Every interval cover of a set of finite outer measure has a countable disjoint subfamily that covers the set up to a null remainder.

Facts & Assumptions

Given: The statement above.

[A1]

We use a cover that is not fine.

Refutation

technique · direct
1.1

Consider the cover of [0,1] by all intervals [0,t] and [t,1] with 0<t<1. It covers every point of [0,1], but it is not fine: for an interior point x, every interval in the cover that contains x has length at least min{x,1x}.

given
2.1

Any two left intervals intersect, and any two right intervals intersect, so a disjoint subfamily contains at most one interval of each type. If it contains only one interval, it obviously misses points of [0,1]. If it contains one left interval [0,s] and one right interval [t,1], disjointness forces s<t, so the open gap (s,t) is uncovered. Thus no disjoint subfamily covers [0,1] up to a null remainder, and the statement is false.

step 1.1

Depends on

Used by

Dependency tree · two levels

6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources