Alphabeta Math
False statementConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedaudited 2026-09-14
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Norm convergence alone does not imply pointwise convergence

Statement

Assume the Axiom of Choice. False claim: the L2-norm convergence conclusion of von Neumann's theorem, by itself, yields pointwise convergence of the same sequence.

Facts & Assumptions

Given: Full choice, Lebesgue probability on [0,1), and the half-open dyadic intervals Iq,k=[k2q,(k+1)2q) for q0 and 0k<2q.

[F1]

Von Neumann gives L2 convergence of ergodic averages (Von Neumann mean ergodic theorem in L2).

[F2]

Birkhoff's pointwise conclusion is proved using the maximal ergodic theorem, not norm convergence alone (Birkhoff pointwise ergodic theorem, Maximal ergodic theorem).

Refutation

technique · constructive norm-convergent sequence
1.1

Enumerate the functions 1Iq,k level by level, listing all 2q intervals at level q before proceeding to level q+1; call the resulting sequence (gn).

construct
2.1

If gn belongs to level q, then [F3] gives gn2=λ(Iq,k)1/2=2q/2. The level tends to infinity with n, so gn0 in L2.

F3step 1.1algebra
2.2

Every x[0,1) lies in exactly one half-open interval at each level. Thus gn(x)=1 once per level and equals 0 at all the other entries of every level q1. Both values occur infinitely often, so (gn(x)) fails to converge for every x.

step 1.1algebra
3.1

Steps 2.1–2.2 show that L2 convergence alone cannot imply full-sequence pointwise convergence. This does not contradict Birkhoff and is not offered as a counterexample among actual ergodic-average sequences: [F2] supplies their pointwise convergence by additional maximal-inequality structure.

F1F2step 2.1step 2.2discharge-construct

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