Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-26
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A c-sparse set has self-density at most c, and a c-dense set has self-density at least 1c1/X

Statement

Let G be a finite simple graph, let c0, and let XV(G) be nonempty.

  1. If X is c-sparse, then dG(X,X)c.
  2. If X is c-dense, then dG(X,X)1c1/X.

Facts & Assumptions

Given: A finite simple graph G, a real c0, and a nonempty set XV(G).

[L1]

A set is c-sparse exactly when every vertex of the induced graph G[X] has degree at most cX (A set is c-sparse exactly when the maximum degree of the graph it induces is at most c times its size, c-sparse, c-dense and c-restricted vertex sets).

[L2]

The self-density is dG(X,X)=eG(X,X)/X2 (Edge counts and densities between nonempty vertex sets).

Proof

technique · direct
1.1

If X is c-sparse, then [L1] bounds every summand in [L3] by cX, so eG(X,X)cX2.

L1L3
2.1

Dividing the inequality of step 1.1 by X2 and using [L2] gives dG(X,X)c.

step 1.1L2algebra
3.1

If X is c-dense, then every vertex of G[X] has at most cX non-neighbours in X{x}, so it has at least X1cX neighbours in X. Summing as in [L3] gives eG(X,X)(1c1/X)X2, and [L2] turns this into dG(X,X)1c1/X.

L3L2givenalgebra

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