Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-26
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A c-sparse set has self-density at most c, and a c-dense set has self-density at least 1−c−1/∣X∣

Statement

Let G be a finite simple graph, let c≥0, and let X⊆V(G) be nonempty.

  1. If X is c-sparse, then dG(X,X)≤c.
  2. If X is c-dense, then dG(X,X)≥1−c−1/∣X∣.

Facts & Assumptions

Given: A finite simple graph G, a real c≥0, and a nonempty set X⊆V(G).

[L1]

A set is c-sparse exactly when every vertex of the induced graph G[X] has degree at most c∣X∣ (A set is c-sparse exactly when the maximum degree of the graph it induces is at most c times its size, c-sparse, c-dense and c-restricted vertex sets).

[L2]

The self-density is dG(X,X)=eG(X,X)/∣X∣2 (Edge counts and densities between nonempty vertex sets).

Proof

technique · direct
1.1L1L3

If X is c-sparse, then [L1] bounds every summand in [L3] by c∣X∣, so eG(X,X)≤c∣X∣2.

2.1step 1.1L2algebra

Dividing the inequality of step 1.1 by ∣X∣2 and using [L2] gives dG(X,X)≤c.

3.1L3L2givenalgebra∎

If X is c-dense, then every vertex of G[X] has at most c∣X∣ non-neighbours in X∖{x}, so it has at least ∣X∣−1−c∣X∣ neighbours in X. Summing as in [L3] gives eG(X,X)≥(1−c−1/∣X∣)∣X∣2, and [L2] turns this into dG(X,X)≥1−c−1/∣X∣.

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