Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-09-01
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An absolutely convergent series has Cauchy partial sums

Statement

Let V be a normed space and let n=0xn be an absolutely convergent series in V. Then the partial sums form a Cauchy sequence in V.

Facts & Assumptions

Given: A normed space V, a sequence (xn) in V, and its partial sums sm:=n<mxn.

[L1]

Absolute convergence means the scalar series n=0xn converges (Series and absolute convergence in a normed space).

[L2]

A convergent scalar series has Cauchy partial sums (Series, partial sums, convergence and the sum, divergence, and the tail series).

Proof

technique · direct
1.1

By [L1] and [L2], for every ε>0 there is N such that n<mxn<ε whenever m>N.

L1L2
1.2

For such m>N, the tail of the vector partial sums satisfies sms=n<mxn.

given
2.1

Applying the triangle inequality to the finite sum in step 1.2 gives smsn<mxn<ε.

step 1.1step 1.2algebra
3.1

Since this holds for every ε>0, the partial sums (sm) are Cauchy in the norm metric, which is exactly the claim.

step 2.1given

Depends on

Used by

Dependency tree · two levels

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Sources