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Universal property of an affine blowup chart

Statement

Let φ ⁣:A→B be a ring map, I⊆A an ideal and a∈I; suppose the image b=φ(a) is a nonzerodivisor in B and IB=bB. Then there is a unique A-algebra homomorphism A[I/a]→B sending x/an to the unique y∈B with x=bny (x∈In); equivalently, Spec⁡B→Spec⁡A[I/a] is the unique A-morphism into the chart Spec⁡A[I/a] along which the image of a generates IOSpec⁡B. The chart A[I/a] itself satisfies the hypothesis with b the image of a.

Facts & Assumptions

Given: A commutative ring A, an ideal I⊆A, an element a∈I, a ring map φ ⁣:A→B whose image b=φ(a) is a nonzerodivisor in B and satisfies IB=bB, and the affine blowup algebra A[I/a] of (Affine blowup algebras: normal form, nonzerodivisors, reducedness, domains) built from the Rees algebra R(I)=⨁n≥0Intn of (The Rees algebra of an ideal and the Rees module of a filtered module).

[F1]

Affine blowup algebras: normal form, nonzerodivisors, reducedness, domains: For a commutative ring A, an ideal I⊆A and a∈I, the affine blowup algebra A[I/a]:=(R(I))(a) is the degree-zero part of the localisation of the Rees algebra R(I) at the multiplicative set generated by at; the image of a in A[I/a] is a nonzerodivisor and IA[I/a]=aA[I/a].

[F2]

The Rees algebra of an ideal and the Rees module of a filtered module: For a commutative ring R and an ideal I⊂R, the Rees algebra is the graded subring R(I)=⨁n≥0Intn⊂R[t]; equivalently, it is the graded ring whose degree-n piece is In.

[F3]

Multiplicative subsets and the localisation S−1R as equivalence classes of fractions: For a commutative ring R and a multiplicative subset S⊆R, the localisation S−1R has elements written r/s with r/s=r′/s′ if and only if u(rs′−r′s)=0 for some u∈S; the operations are r/s+r′/s′=(rs′+r′s)/(ss′) and (r/s)(r′/s′)=rr′/(ss′); every s∈S maps to a unit.

Proof

1.1F1F2F3given

Put β=φ(a). By the fraction description of the affine blowup algebra, every element of C=A[I/a] has the form r/an, r∈In, and r/an=s/am precisely when ak(amr−ans)=0 for some k≥0. Since InB=(IB)n=βnB, there is a unique y∈B with φ(r)=βny: existence follows from this ideal equality and uniqueness from the nonzerodivisor hypothesis on β.

2.1step 1.1

Define ψ(r/an)=y. If r/an=s/am, write φ(r)=βny and φ(s)=βmz. Applying φ to the equality criterion gives βk+m+n(y−z)=0, hence y=z. Thus ψ is well defined. The numerator of the sum is amr+ans, whose image is βm+n(y+z); the product numerator rs has image βm+nyz. Uniqueness of division by βm+n proves additivity and multiplicativity. Degree-zero fractions show that ψ restricts to φ on A and sends 1 to 1.

3.1F1step 2.1∎

Any A-algebra map χ:C→B satisfies βnχ(r/an)=φ(r), because an(r/an)=r in C. Cancellation of βn forces χ(r/an)=ψ(r/an) for every fraction. Hence the map is unique among all A-algebra maps. The chart itself has IC=aC with a a nonzerodivisor, and the affine scheme/ring correspondence gives the stated geometric formulation.

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