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LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedverified 2026-09-23 (gpt-6-sol)
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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A prime minimal over an associated prime plus one element becomes associated after a power quotient

Statement

Assume the Axiom of Choice. Let R be Noetherian, M finite, p∈Ass⁡R(M), and x∈R. If q is minimal over p+(x), then for some n≥1, q∈Ass⁡R(M/xnM).

Facts & Assumptions

Given: The Axiom of Choice and the data in the statement.

[L1]

Under AC, every prime minimal in the support of a finite module over a Noetherian ring is associated (Minimal support primes of a finite module are associated).

Proof

technique · direct
1.1givenconstruct

Embed N=R/p in M. Artin--Rees gives n≥1 such that N∩xnM⊆xN. Hence L=N/(N∩xnM)⊆M/xnM has quotient N/xN≅R/(p+(x)).

2.1L1step 1.1given∎

We have xnN⊆N∩xnM⊆xN. Viewing N as R/p, the annihilator of L therefore lies between p+(xn) and p+(x), so its radical is p+(x). Thus q is minimal in Supp⁡(L) and, under the stated AC, associated to L by [L1]. An associated element of the submodule L has the same annihilator in M/xnM.

Depends on

Used by

Dependency tree · two levels

14 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources