Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-05
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Binary quadratic representation via the Hilbert symbol

Statement

Let a,b,tQv×. Then the binary form aX2+bY2 represents t over Qv if and only if

(at,bt)v=1.

Facts & Assumptions

Given: A place v of Q and nonzero elements a,b,tQv.

[L1]

The Hilbert symbol satisfies (c,d)v=1 exactly when cX2+dY2=1 is soluble over Qv (The Hilbert symbol over a rational completion).

[L2]

The symbol depends only on square classes (The Hilbert symbol is a symmetric bilinear nondegenerate pairing).

Proof

technique · direct
1.1

If aX2+bY2=t has a solution, divide by t to obtain (a/t)X2+(b/t)Y2=1. By [L1], this means (a/t,b/t)v=1. Since (a/t)/(at)=t2 and (b/t)/(bt)=t2 are squares, [L2] gives (at,bt)v=1.

L1L2givenalgebra
2.1

Conversely, if (at,bt)v=1, then [L2] gives (a/t,b/t)v=1, because the two pairs differ by multiplying each entry by the same square t2. By [L1], there exist X,Y with (a/t)X2+(b/t)Y2=1, and multiplying by t yields aX2+bY2=t.

L1L2step 1.1algebra

Depends on

Used by

Dependency tree · two levels

9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources