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LemmaStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (openai/gpt-5.4)audited 2026-07-25
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The Cauchy-sequence reals are Archimedean

Statement

The Cauchy-sequence reals RC\mathbb{R}_C (The reals form a totally ordered field) are Archimedean (Archimedean ordered field): for every xRCx \in \mathbb{R}_C there is a natural number nn with x<n1x < n \cdot 1, where the canonical natural n1n \cdot 1 is the class n^\hat n of the constant rational sequence nn. Equivalently, the canonical naturals (n^)n1(\hat n)_{n \ge 1} are cofinal.

Facts & Assumptions

Given: A real xRCx \in \mathbb{R}_C.

[L1]

Rational approximation: for any real zz and rational ε>0\varepsilon > 0 there is qQq \in \mathbb{Q} with zq^<ε^|z - \hat q| < \hat\varepsilon, and the embedding qq^q \mapsto \hat q preserves and reflects order and arithmetic (The rationals embed densely in the reals).

[L2]

The rationals are Archimedean: for every rational yy there is a natural nn with y<ny < n (The rationals are Archimedean).

[L3]

RC\mathbb{R}_C is a totally ordered field, and q^+r^=q+r^\hat q + \hat r = \widehat{q + r}, 1^=1\hat 1 = 1 (The reals form a totally ordered field, Order on the reals).

[L4]

RC\mathbb{R}_C is Archimedean iff for every real there is a natural nn with the real below the canonical natural n1=n^n \cdot 1 = \hat n (Archimedean ordered field).

Proof

technique · direct
1.1

By [L1] with ε=1\varepsilon = 1 choose a rational qq with xq^<1^|x - \hat q| < \hat 1.

L1choose
1.2

By [L2] applied to the rational q+1q + 1 choose a natural nn with q+1<nq + 1 < n.

L2choose
2.1

From step 1.1, xq^<1^x - \hat q < \hat 1, so x<q^+1^=q+1^x < \hat q + \hat 1 = \widehat{q + 1}.

step 1.1L3
2.2

From step 1.2, since the embedding preserves order, q+1^<n^=n1\widehat{q + 1} < \hat n = n \cdot 1.

step 1.2L1L3L4
3.1

Combining, x<q+1^<n1x < \widehat{q + 1} < n \cdot 1, so x<n1x < n \cdot 1 for this canonical natural.

step 2.1step 2.2L3
4.1

As xRCx \in \mathbb{R}_C was arbitrary, every real lies below some canonical natural: RC\mathbb{R}_C is Archimedean.

step 3.1L4

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 42 results over 19 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources