Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-16
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

If K is characteristic in N and N is normal in G, then K is normal in G

Statement

If K is characteristic in N and N⊴G, then K⊴G.

Facts & Assumptions

Given: Subgroups K≤N≤G with K characteristic in N and N normal in G.

[L1]

A characteristic subgroup is preserved by every automorphism of its ambient group (Characteristic subgroups).

[L2]

A subgroup is normal exactly when conjugation by every ambient element preserves it (Normal subgroup: invariance under conjugation).

[L3]

Conjugation by a fixed group element is an automorphism (Conjugation x↦gxg−1 is an automorphism).

Proof

technique · direct
1.1L2L3

Fix g∈G. Normality of N and [L2] show that conjugation by g maps N to itself; by [L3], its restriction is an automorphism of N.

2.1step 1.1L1L2∎

Since K is characteristic in N, [L1] gives gKg−1=K. This holds for every g∈G, so K⊴G by [L2].

Depends on

Used by

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources