Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-06
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Charpit contact compatibility is preserved

Statement

Let (X,Z,P)(s,y) be a C1 Charpit strip lying in F=0. If Zy(0,y)=P(0,y)Xy(0,y), then

Zy(s,y)=P(s,y)Xy(s,y)

while the strip exists.

Facts & Assumptions

Given: A C1 Charpit strip, its initial contact identity, and the constraint F(X,Z,P)=0.

Proof

technique · direct
1.1

Set D:=ZyPXy. Differentiate the Charpit equations in y and apply the product and chain rules to obtain Ds=FyFzD.

givenalgebra
2.1

Differentiating F(X,Z,P)=0 in y gives Fy=0, so Ds=FzD and D(0,y)=0.

step 1.1givenalgebra
3.1

Multiplication by the integrating factor exp(0sFz(r,y)dr) makes D constant; its initial value is zero, hence D=0.

step 2.1algebra

Depends on

Used by

Dependency tree · two levels

12 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources