Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-09-01
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Prime-power expansion of Chebyshev's psi function

Statement

For every real x≥1,

ψ(x)=∑pk≤xlog⁡p=∑k≥1θ(x1/k),

and both sums are finite.

Facts & Assumptions

Given: A real number x≥1.

[L1]

The von Mangoldt function satisfies Λ(n)=log⁡p when n=pk is a prime power and Λ(n)=0 otherwise (The von Mangoldt function).

[L2]

By definition, ψ(x)=∑n≤xΛ(n) (Chebyshev's psi function).

[L3]

By definition, θ(y)=∑p≤ylog⁡p for every real y≥2 (Chebyshev's theta function).

Proof

technique · direct
1.1L1L2given

Only prime powers contribute to the sum in [L2], by [L1]. Therefore ψ(x)=∑pk≤xlog⁡p, where the sum ranges over all prime powers at most x.

2.1step 1.1givenalgebra

The displayed prime-power sum is finite: if pk≤x, then already 2k≤pk≤x, so k≤log⁡2x; and for each fixed k, only the primes p≤x1/k occur.

3.1L3step 2.1algebra

Fix k≥1. The contribution of the kth prime-power layer is ∑pk≤xlog⁡p=∑p≤x1/klog⁡p=θ(x1/k), by [L3]. Summing these finitely many layers from step 2.1 gives ∑pk≤xlog⁡p=∑k≥1θ(x1/k).

4.1step 1.1step 3.1∎

Combining steps 1.1 and 3.1 proves both displayed identities.

Depends on

Used by

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources