Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-sol)audited 2026-09-27
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Concatenation multiplies rate and relative distance

Statement

Let m≥1, q=2m, K=q/2, let RSq,K⊆Fq q be the Reed-Solomon outer code with rate Ro=K/q and relative distance at least δo, and let Ein=M(⋅):F2m→F216m be the inner encoding of Conditional expectation constructs the inner code deterministically, injective and linear of rate Ri=1/16 and relative distance at least δi, so that wt⁡(Ein(w))≥δi⋅16m for every nonzero w∈F2m. Then the concatenated code of Reed-Solomon outer code and binary linear inner code, which encodes Km bits into 16qm bits, is injective with rate = RoRi = K16q,relative distance ≥ δoδi. For the outer parameters of Reed-Solomon outer code has constant rate and distance and the inner parameters of Conditional expectation constructs the inner code deterministically these are rate at least 12⋅116=132 and relative distance at least 12⋅14=18.

Facts & Assumptions

Given: integers m≥1, q=2m, K=q/2; the bit encoding enc:Fq→F2m of the field, which is F2-linear by the power basis; the outer code RSq,K with rate Ro=K/q and relative distance at least δo; an injective F2-linear Ein:F2m→F216m with wt⁡(Ein(w))≥δi 16m for w≠0.

[F1]

The concatenated encoding sends a message u=(u1,…,uK)∈(F2m)K to the word obtained by applying Ein∘enc to each of the q coordinates of the outer word RSq,K(enc−1(u1),…,enc−1(uK)); it has Km input bits and 16qm output bits, and the field element 0 has bit encoding the zero vector (Reed-Solomon outer code and binary linear inner code).

[F2]

Relative distance of a code of length n over an alphabet is the minimum, over distinct codewords, of the fraction of differing coordinates; over a binary alphabet the coordinates are bits. Rate is the input length in bits divided by the output length in bits (Explicit binary codes of constant rate and distance).

[L1]

Distinct messages of RSq,K have outer words differing in at least δoq coordinates, and distinct messages have distinct outer words (Reed-Solomon outer code has constant rate and distance).

[L2]

The map Ein is linear and injective with wt⁡(Ein(w))≥δi 16m for every nonzero w; in particular u↦Mu has rate Ri=1/16 and relative distance at least δi (Conditional expectation constructs the inner code deterministically).

Proof

technique · direct
1.1

The concatenated encoding is injective: if two messages u≠u′ had the same concatenated word, then their outer words would agree in every coordinate, since Ein∘enc is injective and the blocks of the concatenation are read off coordinatewise; but distinct messages have distinct outer words by [L1, F1]. Moreover the rate is Km/(16qm)=K/(16q)=RoRi, because the outer code has K Fq-symbols (Km bits) and the concatenated word has q blocks of 16m bits.

F1F2L1algebra
2.1

Let u≠u′ be distinct messages with outer words c≠c′, and let S={j:cj≠cj′} be the set of differing coordinates, of size at least δoq by [L1]. For j∈S the field element cj−cj′≠0 has nonzero bit encoding enc(cj−cj′)=enc(cj)−enc(cj′) by linearity of enc, so the block difference Ein(enc(cj))−Ein(enc(cj′))=Ein(enc(cj−cj′)) is a nonzero word of weight at least δi 16m by [L2].

F1L2step 1.1algebra
3.1

The blocks indexed by S occupy disjoint sets of coordinates of the concatenated word, so the total Hamming distance between the two concatenated words is the sum over j∈S of the block weights, at least ∣S∣ δi 16m≥δoq δi 16m; dividing by the word length 16qm gives relative distance at least δoδi, and with the outer and inner parameters this is at least 12⋅14=18 while the rate is 12⋅116=132.

F2step 2.1L1L2algebra∎

Remarks

  • Both factors are honest minima. The outer distance loses a factor q in the number of surviving coordinates and the inner distance loses a factor 16m in the surviving bits per coordinate, and the product is exactly the product of the relative distances; nothing is lost to the intermediate field or to the choice of inner matrix, because the inner map is linear and injective and its blocks are disjoint.
  • The lemma is stated for the concrete outer and inner codes of this page, but the proof uses only [F1], [F2], [L1] and [L2], so the same computation applies to any outer code with rate Ro and relative distance δo whose alphabet is identified with F2m and any injective linear inner code with parameters Ri,δi.

Depends on

Used by

Dependency tree · two levels

12 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources