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LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-09
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Corestriction after transfer multiplies by the index

Statement

Let HG have finite index and M be a left G-module. For every n0, the composite Hn(G;M)TrHn(H;M)iHn(G;M) is multiplication by [G:H]. Here corestriction means the covariant inclusion map in homology; the derived identification retains DC and supplied resolutions.

Facts & Assumptions

Given: The finite-index inclusion, coefficient module, and a finite transversal T.

[F1]

The transfer formula is well-defined on normalized diagonal coinvariants, is a chain map, and induces a transversal-independent homology map (Bar transfer is a chain map independent of the transversal).

[F2]

For right-coset representatives T, write x=r(x)t(x) with r(x)H; transfer is the finite sum obtained by applying r to the vertices of (tg0,,tgn) and using coefficient tm (Finite-index transfer on normalized bar chains).

Proof

1.1

Put u(x)=x. For each tT define the alternating vertex prism Pt,n[(g0,,gn)m]=i=0n(1)i[(r(tg0),,r(tgi),tgi,,tgn)tm]. Expanding the vertex-deletion differential cancels every face away from the switch in pairs; the two endpoint faces that survive give dPt+Ptd=ut,rt,, where ut, uses (tg0,,tgn) and rt, is the t-summand of corestriction after the transfer in [F2]. If tx=httx with htH and txT, then ttx permutes T, r(txg)=htr(txg), and both vertex strings and the coefficient txm=httxm change by the same diagonal translation. Hence P=tTPt descends to G-coinvariants. Equal adjacent input vertices make every prism summand degenerate, so it also descends to normalized chains. Thus dP+Pd=tTut,iTrT.

F1F2givenalgebra
2.1

Each translated summand is [(g0,,gn)m] in diagonal G-coinvariants. The sum is therefore [G:H] times that chain in every degree, including zero. Homotopic chain maps give the same map on homology because their difference on a cycle is a boundary. Thus iTr=[G:H]id.

step 1.1algebra

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