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LemmaStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)
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Countable tower six term limit sequence

Statement

Assume AC. Write L(A)=kerΔA and R(A)=cokerΔA for a countable inverse tower of modules over a fixed ring. A termwise exact sequence of towers 0ABC0 gives a natural exact sequence 0L(A)L(B)L(C)R(A)R(B)R(C)0. If all transitions of a tower A are surjective, then R(A)=0 and each projection L(A)Am is surjective. Removing finitely many initial coordinates induces isomorphisms on both L and R.

Facts & Assumptions

[F1]

Lim one obstruction to completeness defines P(A)=mAm, ΔA(x)m=xmumxm+1, its kernel and its cokernel.

[F2]

The Axiom of Choice permits simultaneous representatives of countably many nonempty cosets and sections of surjective transition maps. These are the uses of AC below.

Proof

Given: The towers in the statement; identify Am with its submodule in Bm. All tower squares commute.

1.1

The map P(B)P(C) is onto: choose a lift in each coordinate by [F2]. If cL(C), lift it to bP(B). Then ΔBbP(A) by commutation, so define c=[ΔBb]. Replacing b by b+a changes the result by ΔAa, hence leaves its class unchanged. Sum and scalar multiple lifts establish linearity.

F1F2
1.2

The map L(A)L(B) is injective coordinatewise. A compatible B tuple whose image in L(C) vanishes lies coordinatewise in A and is still compatible. This proves exactness at L(B) as well.

F1
1.3

Suppose every um is onto. By [F2] choose a right inverse as a set map for each um. For prescribed yP(A) put x0=0 and recursively choose xm+1 with umxm+1=xmym using these sections. Then ΔAx=y, proving R(A)=0. For prescribed xmAm, the same recursion with y=0 constructs later coordinates, while compositions of transitions determine earlier ones. This proves surjectivity of L(A)Am. No sections are asserted linear.

F1F2
1.4

Restriction to mN gives a bijection on compatible tuples: earlier coordinates are forced by the transitions. It is surjective on Delta cokernels because a tail representative can be extended by zero. If a full representative restricts to Δx on the tail, extend x backwards by the finite recursion xm=ym+umxm+1. The original representative is now a full Delta boundary. Hence restriction is also injective on cokernels and is linear. These identifications commute with tower morphisms.

F1
2.1

A compatible B lift of c has zero connecting class. Conversely if c=0, a lift b has ΔBb=ΔAa for some aP(A); then ba is a compatible lift. Thus exactness holds at L(C) in both directions.

step 1.1
2.2

A connecting class becomes zero in R(B). Conversely if aP(A) represents a class becoming zero there, write a=ΔBb. The image c of b is compatible and has c=[a]. This proves exactness at R(A).

F1step 1.1
2.3

If bP(B) maps to ΔCc, lift c to tP(B) as in step 1.1. Then bΔBtP(A) represents the same R(B) class. Every image from R(A) conversely maps to zero in R(C). Finally any representative in P(C) lifts to P(B), proving surjectivity at R(C).

F1step 1.1
3.1

A morphism of the exact tower sequences sends a selected lift to a lift and commutes with Delta. Thus it commutes with ; it plainly commutes with coordinate inclusions and quotient maps too. The entire sequence is natural, including its end terms.

F1step 1.1step 1.2step 2.1step 2.2step 2.3
4.1

The exactness assertions follow from steps 1.2–2.3 and naturality from step 3.1; steps 1.3 and 1.4 prove the two additional claims. Zero modules, zero maps where exactness permits them, and repeated or constant terms cause no exceptions. A single nonzero term followed by zeros has zero L and R by the tail assertion. A constant identity tower has L=A0 and R=0. The index set is the nonempty set of natural numbers; no empty tower is being claimed. All infinite selections were explicitly made in steps 1.1 and 1.3 under AC.

F1step 1.2step 2.1step 2.2step 2.3step 3.1step 1.3step 1.4

Source notes

The local coordinate chase is complete. Boardman section 1 is background for the six-term interface; its omitted chase is supplied above. The owner research argument research/phase-2-next-20-topology-owner-delta-alternatives.md, sections 1–2 and 5, supplied the candidate evaluated here. No source-fetch verification or independent review is inferred.

Depends on

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Sources