Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-adaptedPipeline-generatedprecheck pass
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A keyed permutation stream does not reuse outputs before its counter interval ends

Statement

For a fixed key and counter interval in Counter stream from a keyed finite permutation, distinct counters produce distinct output words. If the interval is the full set {0,…,2w−1}, every word of that finite state set appears exactly once. These are deterministic no-reuse statements; they imply no probabilistic independence.

Facts & Assumptions

Given: A fixed key, a bijection πk:S→S, and the counter procedure of Counter stream from a keyed finite permutation.

[F1]

For a fixed key, the supplied map πk is a bijection of the finite counter set. Counter stream from a keyed finite permutation

Proof

1.1givenF1

If c≠c′ are counters in the interval, injectivity of πk gives πk(c)≠πk(c′). The procedure uses each counter at most once before returning exhausted, so no output repeats in that interval.

2.1F1step 1.1algebra∎

On the full counter set, the injective map πk has 2w distinct outputs in a set of size 2w, hence its range is all of S. Thus every word appears exactly once, with no probability assertion.

Depends on

Used by

Nothing in the library uses this result yet.

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Sources