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LemmaStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-12
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A DFA can realize at most one Nerode class per reachable state

Statement

Let D be a DFA recognizing a language L. If two words u,v∈Σ∗ drive D from its start state to the same state, then u≡Lv. Consequently, distinct Nerode classes of L must reach distinct reachable states of D.

Facts & Assumptions

Given: A DFA D=(Q,Σ,δ,q0,F) recognizing L, with extended transition function δ∗.

[L1]

By Nerode equivalence of words, to prove u≡Lv it is enough to show that uz∈L if and only if vz∈L for every continuation z∈Σ∗.

[L2]

By Acceptance of a word by a DFA and the recognized language, a word w belongs to L exactly when δ∗(q0,w)∈F.

[L3]

By The extended transition function of a DFA, δ∗(s,ε)=s and δ∗(s,xa)=δ(δ∗(s,x),a).

Proof

technique · direct
1.1L3construct

For every state s and words x,z, repeated use of [L3] gives δ∗(s,xz)=δ∗(δ∗(s,x),z); in particular, δ∗(q0,uz)=δ∗(δ∗(q0,u),z) and δ∗(q0,vz)=δ∗(δ∗(q0,v),z).

2.1L1L2step 1.1given

If δ∗(q0,u)=δ∗(q0,v), then step 1.1 implies δ∗(q0,uz)=δ∗(q0,vz) for every z∈Σ∗. By [L2], this gives uz∈L if and only if vz∈L for every z, so [L1] yields u≡Lv.

3.1step 2.1∎

Therefore every reachable state of D contains words from at most one Nerode class, and distinct Nerode classes must land in distinct reachable states.

Depends on

Used by

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources