Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-16
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Every smaller positive exponent is again an Erdős–Hajnal constant

Statement

Let C be a hereditary graph class. If ϵ is an Erdős–Hajnal constant for C and 0<δϵ, then δ is also an Erdős–Hajnal constant for C.

Facts & Assumptions

Given: A hereditary class C, an Erdős–Hajnal constant ϵ for it, and a real δ with 0<δϵ.

[L1]

A positive real c is an Erdős–Hajnal constant for C exactly when every nonempty GC satisfies hom(G)V(G)c, with ac=exp(cloga) for a>0 (The Erdős–Hajnal property and an Erdős–Hajnal constant for a hereditary graph class).

[L3]

The exponential function is strictly increasing on R (The exponential function is strictly increasing).

Proof

technique · direct
1.1

Let GC be nonempty and put n=V(G)1.

given
1.2

If n=1, then nδ=nϵ=1, so the required inequality follows from the one for ϵ.

L1algebra
1.3

If n>1, then logn>0 by [L2], and hence δlognϵlogn.

givenL2algebra
2.1

In the case n>1, [L3] and the real-power convention in [L1] give nδ=exp(δlogn)exp(ϵlogn)=nϵ.

step 1.3L1L3
3.1

In both cases, hom(G)nϵnδ; since G was arbitrary, δ is an Erdős–Hajnal constant for C.

step 1.2step 2.1L1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 49 results over 12 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources