Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-adaptedprecheck passverified 2026-08-03 (gpt-5.6-sol-codex-subscription)
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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The cut at an extremal element is closed under f

Statement

Let (P,≤) be a chain-complete poset, f:P→P progressive, M the smallest admissible set, and x∈M extremal (Extremal element and its cut (Bourbaki–Witt)). Then the cut Mx satisfies f(y)∈Mx for every y∈Mx.

Facts & Assumptions

Given: A chain-complete poset (P,≤), a progressive f:P→P, the smallest admissible set M, an extremal x∈M, and an element y∈Mx.

[A1]

x is extremal: for every z∈M with z<x, f(z)≤x (Extremal element and its cut (Bourbaki–Witt)).

[A2]

Mx={z∈M:z≤x or f(x)≤z} (Extremal element and its cut (Bourbaki–Witt)).

[L1]

M is admissible, so it is closed under f and under suprema of its chains (A smallest admissible set exists, Admissible subset (Bourbaki–Witt)).

[L2]

f is progressive: z≤f(z) for every z∈P (Chain-complete poset).

[L3]

≤ is a partial order: it is reflexive (u≤u) and transitive (u≤v and v≤w imply u≤w), and its strict form u<v means u≤v together with u≠v (Partial order and partially ordered set).

Proof

technique · cases
1.1

Since y∈Mx we have y∈M, and M is closed under f, so f(y)∈M.

A2L1
1.2

Membership of Mx gives y≤x or f(x)≤y, and the relation y≤x holds exactly when y<x or y=x, by the definition of the strict order.

A2L3
1.3

Suppose y<x.

assume-case below
1.4

Suppose y=x.

assume-case equal
1.5

Suppose f(x)≤y.

assume-case above
2.1

In the case y<x, extremality of x gives f(y)≤x, so f(y) lies in M and satisfies f(y)≤x, hence f(y)∈Mx.

step 1.3A1step 1.1A2
2.2

In the case y=x, we get f(y)=f(x), and f(x)≤f(x) by reflexivity, so f(y)∈M satisfies the second alternative, hence f(y)∈Mx.

step 1.4step 1.1A2L3
2.3

In the case f(x)≤y, progressivity gives y≤f(y), so f(x)≤f(y) by transitivity, hence f(y)∈Mx.

step 1.5L2step 1.1A2L3
3.1

The three cases cover every y∈Mx, and each yields f(y)∈Mx.

step 1.2step 2.1step 2.2step 2.3cases-exhaustive∎

Remarks

  • The case y=x is the one that explains the shape of the cut. It is precisely why Mx is defined with f(x)≤z rather than x<z: the image f(x) must itself land inside Mx, and it does so on the upper side.
  • Extremality of x is used only in the first case, and it is exactly what stops f from carrying an element from strictly below x into the forbidden zone strictly between x and f(x). That zone is what the cut omits, and keeping it empty of elements of M is what eventually makes M a chain (The smallest admissible set is a chain).

Depends on

Used by

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources