Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A linear Galerkin V/W cycle is translation-covariant

Statement

For the linear Galerkin V/W-cycle procedure of Finite recursive Galerkin V- and W-cycle for an SPD hierarchy, on any level j and for all x,a,b∈Rnj, Cycle⁡(j,x+a,b+Aja)=a+Cycle⁡(j,x,b). The identity is in exact arithmetic and uses the same hierarchy, smoothing matrices, sweep counts, and cycle count on both sides.

Facts & Assumptions

Given: A finite SPD Galerkin hierarchy, residual-correction pre/post updates, fixed finite sweep and cycle counts, and the exact coarsest solve from Finite recursive Galerkin V- and W-cycle for an SPD hierarchy.

[F1]

Finite recursive Galerkin V- and W-cycle for an SPD hierarchy: a noncoarsest call pre-smooths by x←x+Kpre(b−Ajx), restricts r=b−Ajx, starts the coarse correction at e=0, makes recursive calls with right side PjTr, prolongs by Pje, and post-smooths by the same residual-correction form.

Proof

1.1givenF1algebra

At level j=0, [F1] returns A0−1b. Since A0 is invertible, A0−1(b+A0a)=A0−1b+a, so the identity holds at the base level.

1.2givenF1algebra

At a noncoarsest level, if the current state is shifted from x to x+a and the right side from b to b+Aja, then the residual is unchanged because (b+Aja)−Aj(x+a)=b−Ajx. Each pre-smoothing update in [F1] therefore preserves the shift by a and gives the same fine residual in the two executions.

2.1F1step 1.2algebra

With identical fine residuals, both executions start the coarse correction at e=0 and call the same deterministic recursive procedure with the same right side PjTr. Thus every call returns the same coarse correction e, including every repeated W-cycle call. Prolongation adds the same Pje to both shifted states, and the post-smoothing residuals are again identical, so every post-update preserves the shift.

3.1step 1.1step 1.2step 2.1∎

The base calculation and the noncoarsest calculation establish the stated identity for every level of the finite hierarchy.

Depends on

Used by

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources