Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-09-01
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The standard finite product norms are equivalent

Statement

Let n1 and let E=k<nEk be a finite product of normed spaces, equipped with the three standard product norms of The standard product norms on a finite product of normed spaces. Then for every xE, xmaxx2x1nxmax. Consequently these three norms are equivalent.

Facts & Assumptions

Given: A natural number n1, normed spaces E0,,En1, and a point x=(x0,,xn1)k<nEk.

[L1]

The three product norms are xmax=maxk<nxk, x1=k<nxk, and x2=(k<nxk2)1/2 (The standard product norms on a finite product of normed spaces).

Proof

technique · direct
1.1

For each coordinate, xk2 is one of the nonnegative summands in j<nxj2, so xkx2 for every k and therefore xmaxx2.

L1algebra
1.2

Applying the scalar inequality (ak)2(ak)1 from [L2] to the nonnegative real tuple (x0,,xn1) gives x2x1.

L1L2
1.3

Since every coordinate norm is at most xmax, summing n such bounds gives x1nxmax.

L1algebra
2.1

The three displayed inequalities of steps 1.1, 1.2, and 1.3 are exactly the comparison constants needed for equivalence of the three norms.

step 1.1step 1.2step 1.3

Depends on

Used by

Dependency tree · two levels

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Sources