Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-04
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Finite random variables are measurable

Statement

Let (Ω,w) be a finite probability space, and regard it as the probability space (Ω,P(Ω),Pw) from Finite probability spaces are exactly finite full-power-set probability spaces. Then every function X:ΩR is a real random variable.

In particular, the published finite definition Real random variables on finite probability spaces and their finite distributions is exactly the measure-theoretic definition on that full-power-set probability space.

Facts & Assumptions

Given: A finite probability space (Ω,w) and a function X:ΩR.

[L1]

The theorem on finite probability spaces identifies (Ω,w) with a probability measure on (Ω,P(Ω)) (Finite probability spaces are exactly finite full-power-set probability spaces).

[L2]

A real random variable is a measurable map from the sample-space sigma-algebra to (R,B(R)) (Random elements and real random variables).

[L3]

On a finite probability space, a real random variable is simply a function ΩR (Real random variables on finite probability spaces and their finite distributions).

Proof

technique · direct
1.1

By [L1], every subset of Ω is measurable. Hence for every Borel set BR, the preimage X1(B) is a subset of Ω, so it lies in P(Ω). Therefore X is measurable.

L1L2
2.1

Step 1.1 proves that every finite random variable in the sense of [L3] is a real random variable in the sense of [L2], so the two notions agree exactly on finite full-power-set probability spaces.

step 1.1L2L3

Depends on

Used by

Dependency tree · two levels

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Sources