Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedPipeline-generatedjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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Fundamental normal surfaces are connected

Statement

Every nonempty fundamental normal surface in a finite tetrahedral triangulation of a compact piecewise-linear 3-manifold is connected.

Statement references

Normal-surface coordinates and the Haken cone — a normal surface has a finite normal-coordinate vector and fundamentalness means no nonzero admissible decomposition.

Hass–Lagarias–Pippenger, Lemma 5.3 — fundamental normal surfaces are connected.

Erickson, “Normal Surfaces and Knots,” §14.3 — connectedness of fundamental normal surfaces.

Facts & Assumptions

Given: A nonempty fundamental normal surface S in a finite tetrahedral triangulation.

[F1]

Normal-surface coordinates and the Haken cone: v(S) is an admissible integer vector and fundamentalness excludes every decomposition into two nonzero admissible integer vectors.

Proof

1.1givenF1construct

Suppose S is disconnected. Since S is a finite normal surface, its connected components are finite in number; let S1 be one component and let S2 be the union of all remaining components. Both are nonempty properly embedded normal surfaces: each normal disk and each face-matched arc belongs to exactly one component. Disk counts add coordinatewise, so v(S)=v(S1)+v(S2), and both summands are admissible nonzero integer vectors.

2.1F1step 1.1contradiction∎

The decomposition in step 1.1 contradicts the defining indecomposability of the fundamental vector v(S). Therefore S is connected.

Depends on

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Sources