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Germs of orientation-preserving diffeomorphisms of the line at zero are torsion-free
Statement
Every finite subgroup of the group of germs at of orientation-preserving local diffeomorphisms of fixing is trivial: if is such a germ and in the group of germs for some , then . Equivalently, the group of germs of orientation-preserving local diffeomorphisms fixing a point of a one-dimensional manifold is torsion-free.
Facts & Assumptions
Given: A germ and a positive integer with in the group of germs.
A germ of local diffeomorphisms of at fixing is an equivalence class of local diffeomorphisms with , , two representatives being equivalent when they agree on a neighbourhood of ; the product is represented by the composite and the group structure is as in Germs of local diffeomorphisms at a point form a group (Germs of local diffeomorphisms at a point).
Composition of representatives induces a well-defined associative operation with identity and inverses on , so it is a group, and an element is the identity germ exactly when one (equivalently every) representative equals the identity on a neighbourhood of (Germs of local diffeomorphisms at a point form a group).
A local diffeomorphism of is a map with local inverse; an orientation-preserving one fixing has positive derivative at and is therefore strictly increasing on a neighbourhood of (Diffeomorphisms and local diffeomorphisms of manifolds).
Proof
(A representative with controlled iterates.) By [F1, F2] choose a representative defined on an open interval containing , with and orientation-preserving; by [F3] has positive derivative at and is strictly increasing on a neighbourhood of . Since is the identity germ, some neighbourhood of is mapped identically by [F2]. First shrink so is strictly increasing throughout . Continuity at the fixed point then gives an open interval so that on and every iterate , , lies in [F1, F2, F3].
(No displacement.) Suppose is not the identity germ. Then, by [F2], for every neighbourhood of there is a point of that neighbourhood with . Choose such a point . If , then strict increase of on gives for every , hence , contradicting ; if , the same monotonicity gives and , again a contradiction. Hence no such exists and agrees with the identity on a neighbourhood of , that is, as a germ.
(Finite subgroups.) Let be a finite subgroup and let . The cyclic subgroup generated by is contained in , hence finite, so for some ; step 2.1 applied with that gives . Therefore every element of is the identity germ and is the trivial subgroup: the group of germs is torsion-free.
For a one-dimensional manifold and , choose a chart at ; a germ of an orientation-preserving local diffeomorphism of at is represented in this chart by a germ of an orientation-preserving local diffeomorphism of at , and composition and the identity are preserved by the chart change. Hence the same argument shows that the group of germs at is torsion-free.
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Sources
- Leiden NCG seminar, Noncommutative Geometry of Foliations (2023 seminar notes; complete PDF) (standard reference, not scraped)
- Danny Calegari, Foliations and the Geometry of 3-Manifolds (Oxford Mathematical Monographs; complete author-hosted PDF) (standard reference, not scraped)