Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passaudited 2026-09-27
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Closed graphs over separated targets

Statement

Let g:X→Y be an S-morphism of schemes and suppose that Y→S is separated. Then the graph Γg:X→X×SY is a closed immersion. No separatedness hypothesis on X→S is required.

Facts & Assumptions

Given: An S-morphism g:X→Y with Y→S separated, and the graph Γg.

[F1]

The graph morphism is Γg=(id⁡X,g):X→X×SY, supplied by Existence of all scheme fibre products; its first projection is the identity and its second projection is g. (The graph morphism over a base)

[F2]

With H=(gpr⁡X,pr⁡Y):X×SY→Y×SY, the square with top arrow Γg, bottom arrow ΔY/S, left arrow g and right arrow H is Cartesian; thus Γg is the base change of ΔY/S along H. (The graph is a pullback of the diagonal)

[F3]

A morphism Y→S is separated when ΔY/S is a closed immersion. (Separated morphism of schemes)

[F4]

Closed immersions remain closed immersions after arbitrary base change; this is asserted with no flatness or finiteness hypothesis. (Base change of immersions)

Proof

technique · direct
1.1

By [F1] the graph Γg:X→X×SY is the morphism (id⁡X,g), and [F2] exhibits it as the base change of ΔY/S:Y→Y×SY along H:X×SY→Y×SY, the square in [F2] being Cartesian.

F1F2given
1.2

Since Y→S is separated, [F3] says that ΔY/S is a closed immersion.

F3given
2.1

The base change of the closed immersion ΔY/S along H is a closed immersion by [F4]; by step 1.1 that base change is Γg, so Γg is a closed immersion.

F4step 1.1step 1.2
3.1

The argument used only the separatedness of Y→S and the Cartesian square of [F2]; nothing was assumed about X→S, which may even be nonseparated.

step 2.1∎

Depends on

Used by

Dependency tree · two levels

17 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources