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LemmaStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-26
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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Growth comparison is a preorder

Statement

On nondecreasing functions N→N, the relation ≼ of Growth comparison and growth type is reflexive and transitive. Consequently ≃ is an equivalence relation.

Facts & Assumptions

Given: Nondecreasing functions f,g,h:N→N.

[L1]

The relation f≼g means that some natural number C≥1 satisfies f(n)≤C g(Cn+C)+C for every n∈N, and f≃g means both f≼g and g≼f (Growth comparison and growth type).

Proof

technique · direct
1.1L1given

Reflexivity holds with C=1, since f(n)≤f(n+1)+1 for every n and f is nondecreasing. So f≼f.

1.2L1givenalgebra

Suppose f≼g via C1 and g≼h via C2. Put C:=C1C2+C1+C2, which is again a natural number with C≥1. Then f(n)≤C1g(C1n+C1)+C1≤C1C2 h(C2(C1n+C1)+C2)+C1C2+C1+C2, and the argument of h is at most Cn+C. Since h is nondecreasing and C≥C1C2, this gives f(n)≤C h(Cn+C)+C for every n. Hence f≼h.

2.1L1step 1.1step 1.2∎

Steps 1.1 and 1.2 make ≼ a preorder. The relation ≃ is therefore an equivalence relation by definition.

Depends on

Used by

Dependency tree · two levels

2 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources