Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-14
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Finite word-calculus rearrangement

Statement

For every positive integer d,

a1adx1xd d A1Adx1xd.

Facts & Assumptions

Given: A positive integer d and the two displayed endpoint words.

[F1]

The language Ld, elementary commutations, matched-pair replacement, finite block permutation, and d are exactly the finite calculus in the preceding definition. The finite word calculus for the Halpern–Läuchli argument

Proof

technique · induction on $d$
1.1

Write Um=a1am, Xm=x1xm, Em=A1Am, and Vm=x1xm. For d>1 there is a bridge adEd1Vd1xddAdUd1Xd1xd: Rule 3 moves Ed1 left of ad; Rule 1 rearranges the middle as (Aixi)i=1d1adxd; Rule 2 changes all d matched pairs to (aixi)i=1d1Adxd; Rule 1 moves each earlier xi past later universal a-symbols and commutes the existential symbols to give Ud1AdXd1xd; and Rule 3 moves Ad left of Ud1.

F1
1.2

Derivations in Ld1 lift through either outside matched pair: Wd1W implies both adWxddadWxd and AdWxddAdWxd. It suffices to lift one rule step. Rules 1 and 2 apply unchanged inside the context. For Rule 3, Rule 1 first rearranges its adjacent prefix of a- and A-symbols into a universal block followed by an existential block, Rule 3 exchanges the blocks, and Rule 1 restores the required order. The outside coordinate remains a complete ordered pair; induction on the finite derivation length proves both implications.

F1
1.3

If d=1, the asserted derivation is exactly a1x11A1x1, an instance of Rule 2.

F1base
2.1

Suppose d>1 and the result holds in dimension d1. Rule 1 gives UdXddadUd1Xd1xd. Lift the induction hypothesis by the first implication in step 1.2, apply the bridge from step 1.1, and lift the induction hypothesis by the second implication in step 1.2; thus adUd1Xd1xddadEd1Vd1xddAdUd1Xd1xddAdEd1Vd1xd. Rule 1 finally commutes the A-symbols and the x-symbols to obtain EdVd.

F1step 1.1step 1.2ih
3.1

Every intermediate word lies in Ld: elementary commutation changes no coordinate's selected pair, Rule 2 replaces one legal ordered pair by the other, and Rule 3 is invoked only with its result in Ld. Steps 1.3 and 2.1 therefore prove the assertion for every positive d.

F1step 1.3step 2.1discharge-induction

Depends on

Used by

Dependency tree · two levels

2 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources