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Laurent coefficients on Hartogs slices depend holomorphically on the remaining variables
Statement
Fix , let be holomorphic on , and choose with . For each integer and each with , define
Then every is holomorphic on the unit disc . Moreover, for each fixed with the slice has Laurent expansion
Facts & Assumptions
Given: Real numbers are not assumed; only , a function , and a radius with .
The Hartogs figure contains every point with and (The Hartogs figure H(r,s) and its bidisc hull).
A contour integral of a jointly continuous integrand that is holomorphic in the parameter variable defines a holomorphic function of that parameter (A contour integral of a jointly continuous, parameter-holomorphic integrand is holomorphic).
The Laurent coefficients of a one-variable holomorphic function on an annulus are given by the contour integral formula, and those coefficients are unique (Laurent coefficients are given by contour integrals and are unique).
Proof
Fix an integer . By [L1], for and the point lies in , so the integrand is continuous on the circle times the unit disc and, for fixed , holomorphic in . Therefore [L2] makes holomorphic on .
Fix with . Then the slice is holomorphic on the annulus , again by [L1]. Applying [L3] to that one-variable slice on the circle shows that its Laurent coefficients are exactly the numbers defined above.
The Laurent expansion from step 1.2 is therefore for , and step 1.1 gives the holomorphic dependence of every coefficient on .
Depends on
Used by
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Sources
- J. Lebl, Tasty Bits of Several Complex Variables, §2.1 (standard reference, not scraped)