Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-27
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Laurent coefficients on Hartogs slices depend holomorphically on the remaining variables

Statement

Fix 0<r,s<1, let f be holomorphic on H(r,s), and choose ρ with r<ρ<1. For each integer n and each w with w<1, define

an(w):=12πiζ=ρf(ζ,w)ζn+1dζ.

Then every an is holomorphic on the unit disc {w<1}. Moreover, for each fixed w with w<1 the slice zf(z,w) has Laurent expansion

f(z,w)=nZan(w)zn(r<z<1).

Facts & Assumptions

Given: Real numbers 0<r<s<1 are not assumed; only 0<r,s<1, a function fO(H(r,s)), and a radius ρ with r<ρ<1.

[L1]

The Hartogs figure contains every point (ζ,w) with ζ=ρ and w<1 (The Hartogs figure H(r,s) and its bidisc hull).

[L2]

A contour integral of a jointly continuous integrand that is holomorphic in the parameter variable defines a holomorphic function of that parameter (A contour integral of a jointly continuous, parameter-holomorphic integrand is holomorphic).

[L3]

The Laurent coefficients of a one-variable holomorphic function on an annulus are given by the contour integral formula, and those coefficients are unique (Laurent coefficients are given by contour integrals and are unique).

Proof

technique · direct
1.1

Fix an integer n. By [L1], for ζ=ρ and w<1 the point (ζ,w) lies in H(r,s), so the integrand (ζ,w)f(ζ,w)ζn1 is continuous on the circle times the unit disc and, for fixed ζ, holomorphic in w. Therefore [L2] makes an holomorphic on {w<1}.

L1L2
1.2

Fix w with w<1. Then the slice zf(z,w) is holomorphic on the annulus r<z<1, again by [L1]. Applying [L3] to that one-variable slice on the circle z=ρ shows that its Laurent coefficients are exactly the numbers an(w) defined above.

L1L3
2.1

The Laurent expansion from step 1.2 is therefore f(z,w)=nZan(w)zn for r<z<1, and step 1.1 gives the holomorphic dependence of every coefficient on w.

step 1.1step 1.2

Depends on

Used by

Dependency tree · two levels

25 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources