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LemmaStatement: AI-adaptedProof: AI-generatedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-31
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Homotopic maps have chain-isomorphic mapping cones

Statement

If chain maps f,g:C∙→D∙ are chain-homotopic, then Cone⁡(f) and Cone⁡(g) are isomorphic as chain complexes.

Facts & Assumptions

Given: Chain maps f,g:C∙→D∙ and a chain homotopy s:f≃g.

[L1]

A chain homotopy satisfies f−g=dDs+sdC (A chain homotopy).

[L2]

The cone differential is d(y,x)=(dD(y)+f(x),−dC(x)) (The mapping cone of a chain map).

Proof

technique · direct
1.1L1L2givenconstructalgebra

Define Φn:Cone⁡(f)n→Cone⁡(g)n by Φn(y,x):=(y+sn−1(x),x). Using [L2], the equality g−f=−(f−g), and then [L1], one checks dCone⁡(g)Φ=ΦdCone⁡(f).

2.1L1step 1.1algebra∎

Replacing s by −s gives the inverse block map Ψn(y,x):=(y−sn−1(x),x). Thus Φ is a chain isomorphism between the two mapping cones.

Depends on

Used by

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources