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The weighted trajectory space is complete

Statement

If E is finite-dimensional and complete, then (Cη(E),∥⋅∥η) is a Banach space for every η>0. No choice principle is used.

Facts & Assumptions

Given: A finite-dimensional complete normed space E, η>0, and the space Cη(E) of Weighted trajectory space for a local center-manifold construction.

[F1]

Weighted trajectory space for a local center-manifold construction: ∥u∥η=sup⁡t∈Re−η∣t∣∥u(t)∥.

[F2]

R and Rn for n≥1 with the Euclidean metric are complete, componentwise from the Cauchy criterion in R proves completeness of R and of Euclidean Rn for n≥1. In the present lemma, completeness of E in its specified norm is a hypothesis, including when E={0}.

Proof

Given: E, η, and Cη(E) as above.

1.1F1constructalgebra

Define Jηu(t):=e−η∣t∣u(t). This is a linear isometry from Cη(E) onto Cb(R,E) with the supremum norm: its inverse sends g to u(t)=eη∣t∣g(t), and both maps preserve continuity and the displayed norms.

1.2F2givenchoose

Let (gn) be Cauchy in Cb(R,E). For each t, (gn(t)) is Cauchy in E, so define g(t) to be its unique limit. Given ε>0, choose N such that sup⁡t∥gn(t)−gm(t)∥<ε/3 for n,m≥N; letting m tend to infinity pointwise gives sup⁡t∥gn(t)−g(t)∥≤ε/3 for n≥N. Thus gn→g uniformly, which makes g continuous, and the same bound with one fixed n≥N shows g is bounded. Pointwise uniqueness defines g without choice.

2.1step 1.1step 1.2∎

Therefore Cb(R,E) is complete, and the isometry in step 1.1 transfers completeness to Cη(E).

Remarks

This result supplies only completeness of the trajectory space. The contraction used to construct the center manifold is verified separately in A parameterized C5 center manifold exists at a simple Hopf spectral split.

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Sources