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LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-13
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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A cone over an identity diagram is weakly initial, and the identity diagram has a limit exactly when the category has an initial object

Statement

A cone λ:ΔL⇒1C supplies a morphism from L to every object of C, so L is weakly initial. The possibly large identity diagram 1C:C→C has a limit if and only if C has an initial object; in that event every limiting apex is initial.

Facts & Assumptions

Given: A category C and its identity diagram.

[F1]

Completeness concerns all small diagrams and makes no assertion about a large identity diagram (Finite, small, and large limits and colimits; complete and cocomplete categories).

[F2]

An initial object I has exactly one morphism I→C for every object C (Initial object, terminal object, and zero object).

Proof

technique · universal property
1.1

A cone λ has a leg λC:L→C for every object C, so its apex is weakly initial.

given
1.2

Suppose λ is limiting. Both 1L and λL are morphisms from the cone λ to itself, because naturality gives λCλL=λC. Limit uniqueness yields λL=1L.

given
1.3

Conversely, let I be initial. The unique maps iC:I→C form a cone: for f:C→C′, both fiC and iC′ are maps I→C′, hence equal by [F2].

F2
2.1

For any f:L→C, cone naturality for f says fλL=λC. By step 1.2, f=λC. Thus exactly one morphism L→C exists, and [F2] makes L initial.

F2step 1.2
2.2

For any cone ξ:ΔX⇒1C, take u:=ξI:X→I. Naturality along iC:I→C gives iCu=ξC. If v:X→I is another cone morphism, its equation at I is iIv=ξI; since iI=1I, v=u. The cone of step 1.3 is limiting.

F2step 1.3
3.1

Steps 1.2, 2.1, 1.3, and 2.2 prove both directions. If C is large, [F1] explains why this conclusion is not supplied merely by completeness.

F1step 2.1step 2.2∎

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources