Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-sol)audited 2026-09-27
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Frobenius reciprocity for class functions

Statement

Let G be a finite group, let H≤G be a subgroup, let θ∈cf(H) be a class function on H, and let ψ∈cf(G) be a class function on G. Then

⟨Ind⁡HGθ, ψ⟩G=⟨θ, Res⁡HGψ⟩H.

Facts & Assumptions

Given: A finite group G, a subgroup H≤G, a class function θ on H, a class function ψ on G, and the induced and restricted class functions Ind⁡HGθ and Res⁡HGψ of Induced class functions and restricted class functions.

[F1]

Restriction of class functions is the restriction map ψ↦ψ∣H, induction is the C-linear map θ↦Ind⁡HGθ given by the Frobenius formula, and for an honest character χ of H the class function Ind⁡HGχ is the honest induced character (Induced class functions and restricted class functions).

[F2]

The irreducible complex characters φ1,…,φs of H form an orthonormal basis of cf(H), and the irreducible complex characters χ1,…,χr of G form an orthonormal basis of cf(G) (The irreducible complex characters form an orthonormal basis of cf(G), An irreducible complex character).

[F3]

The inner product ⟨α,β⟩=1∣G∣∑g∈Gα(g)β(g)‾ is linear in its first argument and conjugate-linear in its second, on cf(G) as well as on cf(H) (The standard inner product on cf(G)).

[F4]

For complex characters χ of H and ψ′ of G one has ⟨Ind⁡HGχ,ψ′⟩G=⟨χ,Res⁡HGψ′⟩H (Frobenius reciprocity for complex characters).

[F5]

A class function on a finite group is determined by its values on conjugacy classes, and the space of class functions is a complex vector space (Class functions and the complex vector space cf(G)).

Proof

technique · direct
1.1

Since the irreducible characters form orthonormal bases, there are unique complex numbers a1,…,as and b1,…,br with θ=∑i=1saiφi and ψ=∑j=1rbjχj.

F2F5given
2.1

By the linearity of induction in [F1], Ind⁡HGθ=∑iaiInd⁡HGφi, and the functions Ind⁡HGφi are the honest induced characters of the characters φi; likewise Res⁡HGψ=∑jbjRes⁡HGχj.

F1step 1.1
3.1

The inner product is linear in the first argument and conjugate-linear in the second, by [F3] on G and on H respectively, so bilinearity and the expansions of step 2.1 give ⟨Ind⁡HGθ,ψ⟩G=∑i,jaibj‾⟨Ind⁡HGφi,χj⟩G and ⟨θ,Res⁡HGψ⟩H=∑i,jaibj‾⟨φi,Res⁡HGχj⟩H.

F3step 2.1
3.2

For every pair of indices i,j the honest-character reciprocity [F4] applies to the character φi of H and the character χj of G, giving ⟨Ind⁡HGφi,χj⟩G=⟨φi,Res⁡HGχj⟩H; by step 2.1 the left-hand side is the same as ⟨Ind⁡HGφi,χj⟩G computed with the induced class function.

F1F4step 2.1
4.1

Substituting the identities of step 3.2 into the two expansions of step 3.1 makes the sums equal term by term, so ⟨Ind⁡HGθ,ψ⟩G=⟨θ,Res⁡HGψ⟩H, as claimed. ∎

step 3.1step 3.2

Depends on

Used by

Dependency tree · two levels

20 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources