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Real powers of the Japanese bracket act on Schwartz space
Statement
For every integer and real , the functions are smooth multipliers acting continuously on . The multiplication maps are mutual inverses. By transposition they also act continuously and invertibly on , for both its weak and strong dual topologies.
Facts & Assumptions
Given: , , and the bracket .
Schwartz functions are actual smooth functions, and their topology is given by the seminorms (Schwartz space and its seminorms).
A smooth multiplier whose every derivative has polynomial growth acts continuously on ; its transpose acts continuously on for both dual topologies (Smooth polynomially bounded multipliers on schwartz space).
Proof
Put . Induction on , differentiating either the polynomial factor or , expresses each derivative as a finite sum where every is a polynomial of degree at most . Since , each term is bounded by a constant times , and hence by . Enlarging the exponent to an integer gives a polynomial-growth bound for this derivative.
The same induction with gives a polynomial-growth bound for every derivative of .
The bounds in steps 1.1 and 2.1 meet the hypotheses of [F2], so multiplication by either weight is continuous on Schwartz space. Pointwise , so both compositions on are the identity.
For , transposition defines . By [F2] these maps are continuous for the weak and strong dual topologies; their compositions evaluate on , so they are inverse on .
Depends on
Used by
- Japanese-bracket and Laplacian Bessel-potential operators Definition
- Weighted Fourier candidate norm on Schwartz space Definition
- A Dirac mass has precisely sufficiently negative Sobolev order Example
- Every Schwartz function belongs to every real-order Hˢ Example
- Bessel potentials shift Sobolev order Lemma
- Weighted Fourier transforms of Schwartz functions are dense in L2 Lemma
- Real-order Hˢ as weighted Fourier distributions Theorem
- The Bessel completion embeds canonically in tempered distributions Theorem
- Weighted tempered-distribution characterization of Hˢ Theorem
Dependency tree · two levels
8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Semyon Dyatlov, Lecture Notes for 18.155, current revision (standard reference, not scraped)
- Richard B. Melrose, Differential Analysis, Chapter 3 (standard reference, not scraped)