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Kleene star is the least concatenation-closed language containing and
Statement
Let be a language over an alphabet .
- .
- .
- If is a language with and , then .
In particular, is the least language containing and closed under left concatenation by words from ; therefore it is also the least concatenation-closed language containing and .
Facts & Assumptions
Given: A language and a language .
The powers of satisfy , for the set consists of words with each , and by Language concatenation, powers, and Kleene star.
Language concatenation is by Language concatenation, powers, and Kleene star.
Proof
By [L1], . This proves clause 1.
Let . By [L2] there are and with . Since , [L1] gives some with . Then by the definition of in [L1], so again. Thus , proving clause 2.
Assume and . We prove by induction on that . For , [L1] gives .
For the induction step, assume . If , then by [L1] there are and with . The induction hypothesis gives , so . Hence .
If , choose with and . Writing and with every , the concatenation is the -fold product , so . Therefore , and is concatenation-closed.
Any concatenation-closed language containing and satisfies , because for and the concatenation lies in .
By steps 1.3 and 1.4, every is contained in . Since by [L1], we get . This proves clause 3.
Step 1.1 gives , and [L1] gives . Together with step 1.5, this shows that is itself a concatenation-closed language containing and . Now step 2.1 and step 1.6 show that every other such language contains . This is exactly the stated minimality.
Depends on
Used by
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Dependency tree · two levels
4 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Jean Gallier and Jocelyn Quaintance, Introduction to the Theory of Computation: Some Notes for CIS511 (standard reference, not scraped)