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Convergence and composition of Morse tangle integrals

Statement

Let T1⊂C×[a,c] and T2⊂C×[c,b] be compact strict Morse tangles whose boundary points and orientations match at the regular level c, with the joined tangle T=T2∘T1 smooth and embedded. Their unframed configuration integrals converge absolutely degreewise and satisfy

Z(T2∘T1)=Z(T2) Z(T1),

where multiplication stacks tangle diagrams with T2 above T1. The equality holds in the completed unframed tangle diagram space and uses only the finite-degree integrals defined on the matched pieces.

Facts & Assumptions

Given: Matched compact strict Morse tangles T1,T2, their regular joining level c, and the unframed degreewise tangle integrals.

[F1]

The Kontsevich integral on parenthesized braids: Z(T) integrates over the ordered levels on a compact tangle skeleton, sums pairings at each level, and places the upper tangle factor to the left in the vertical-stacking product.

[F2]

Convergence and needle estimates for Kontsevich integrals: for each fixed degree, the tangle pairing sum is an absolutely convergent improper integral in the unframed 4T+1T quotient.

Proof

Given: As above. Fix a degree m and work with its finitely many branch chambers and pairing types.

1.1givenF1F2algebra

In the degree-m ordered simplex, the set where some level tj=c has measure zero. Absolute convergence from [F2] allows removal of this set without changing the integral. The remaining domain is the disjoint union, for k=0,…,m, of regions with exactly k levels above c and m−k below it; each such region is the product of the corresponding ordered simplex for T2 and that for T1.

2.1F1step 1.1constructalgebra

On the region indexed by k, every selected pair at a level above c lies on T2, and every pair below c lies on T1. Thus a pairing on the composite decomposes uniquely into a pairing on each piece. The product differential form separates into the upper and lower factors in height order, and the resulting chord diagram is their vertical stack.

3.1F1F2step 2.1algebra∎

Fubini's theorem applies to each product region because both factors are absolutely integrable by [F2]. Therefore its integral is the product of the degree-k coefficient for T2 and the degree-(m−k) coefficient for T1. Summing over the finite set k=0,…,m is exactly the degree-m coefficient convolution of Z(T2)Z(T1). Since m was arbitrary, the displayed completed-series identity follows.

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