Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + claude-sonnet-5)audited 2026-08-17
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

For a member A of a lambda-system D, the sets B with A intersection B in D form a lambda-system

Statement

Let D be a lambda-system on X and fix A∈D. Then

DA:={B∈D:A∩B∈D}

is a lambda-system on X.

Facts & Assumptions

Given: A lambda-system D on X and a fixed set A∈D.

[L1]

A lambda-system contains X, is closed under relative differences, and is closed under increasing countable unions (Lambda-systems, or Dynkin systems).

Proof

technique · direct
1.1givenL1

One has X∈D and A∩X=A∈D, so X∈DA.

1.2L1algebra

If B,C∈DA and B⊆C, then C∖B∈D and A∩(C∖B)=(A∩C)∖(A∩B)∈D by [L1]; hence C∖B∈DA.

2.1L1algebra∎

If (Bn) is increasing in DA, then ⋃nBn∈D and A∩⋃nBn=⋃n(A∩Bn)∈D by [L1]. Therefore ⋃nBn∈DA, and all lambda-system axioms hold.

Depends on

Used by

Dependency tree · one level

1 result within one dependency step of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources