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LMNN hinge subgradient formula and a uniform data-dependent bound

Statement

Fix the finite labeled sample, fixed target sets, and μ∈[0,1] of the LMNN objective. For each j∈Ni and each impostor index l with yl≠yi, set Cij=(xi−xj)(xi−xj)T, Dijl=Cij−Cil, and hijl(M)=1+⟨M,Dijl⟩F, where ⟨A,B⟩F=∑r,sArsBrs. Define γijl(M)=1 if hijl(M)>0 and γijl(M)=0 if hijl(M)≤0. Put

G(M)=(1−μ)∑i∑j∈NiCij+μ∑i∑j∈Ni∑l:yl≠yiγijl(M)Dijl.

For the convex objective Fμ on S+d, a Frobenius subgradient at M means a symmetric matrix G such that Fμ(N)≥Fμ(M)+⟨G,N−M⟩F for every N∈S+d. Then G(M) is a subgradient at every M∈S+d. Moreover, uniformly in M,

∥G(M)∥F≤Bdata:=(1−μ)∑i∑j∈Ni∥xi−xj∥22+μ∑i∑j∈Ni∑l:yl≠yi(∥xi−xj∥22+∥xi−xl∥22).

At an exact hinge kink hijl(M)=0, the selected subgradient coefficient is 0.

Facts & Assumptions

Given: The finite sample, fixed target sets and weight μ in the Statement, and M∈S+d.

[F1]

The objective is the finite weighted sum of linear pull terms and positive-part hinge terms with affine arguments (Fixed-target large-margin nearest-neighbor objective).

[F2]

The objective is convex on S+d (The fixed-target LMNN objective is convex).

[F3]

A subgradient is a vector whose inner product gives a global supporting affine lower bound on the convex function (Subgradients and the subdifferential of a convex function).

[F5]

The Euclidean norm on Rd satisfies ∥a∥22=∑rar2 (The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn).

Proof

1.1F1algebra

For aij=xi−xj, the entrywise inner product satisfies ⟨M,Cij⟩F=∑r,sMrs(aij)r(aij)s=aijTMaij=qM(xi,xj). Thus each hinge has the form ϕ(M)=max⁡{0,1+⟨M,Dijl⟩F}, with affine argument hijl(M).

1.2F4F5algebra

For any a∈Rd, ∥aaT∥F2=∑r,s(aras)2=(∑rar2)2, so ∥Cij∥F=∥xi−xj∥22 by [F5]. By [F4], ∥Dijl∥F≤∥Cij∥F+∥Cil∥F=∥xi−xj∥22+∥xi−xl∥22.

2.1step 1.1algebra

If hijl(M)>0, then ϕ(M)=hijl(M) and ϕ(N)≥hijl(N)=ϕ(M)+⟨Dijl,N−M⟩F for every N. If hijl(M)≤0, then ϕ(M)=0 and ϕ(N)≥0=ϕ(M)+⟨0,N−M⟩F for every N. Hence γijl(M)Dijl is a subgradient of this hinge, including the selected zero coefficient at equality.

3.1step 1.1step 2.1F2F3algebra

Each Cij and Dijl is symmetric, so their weighted sum G(M) is symmetric. Each pull term is linear with Frobenius subgradient Cij. Adding its supporting equality to the hinge supporting inequalities in step 2.1, weighted by the nonnegative coefficients 1−μ and μ, proves Fμ(N)≥Fμ(M)+⟨G(M),N−M⟩F for every N∈S+d. Thus G(M) is a subgradient by [F3].

4.1step 1.2givenF4algebra∎

Since each γijl(M)∈{0,1}, the triangle inequality and step 1.2 give ∥G(M)∥F≤(1−μ)∑i∑j∈Ni∥Cij∥F+μ∑i∑j∈Ni∑l:yl≠yi∥Dijl∥F≤Bdata. The bound is finite because the sample and all index sets are finite, and it is independent of M.

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