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LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-05
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A local morphism of stalks induces a residue-field map

Statement

Let

(f,f♯):(X,OX)→(Y,OY)

be a morphism of locally ringed spaces, and let x∈X. Then the local stalk map

fx♯:OY,f(x)⟶OX,x

induces a field homomorphism

κ(f(x))⟶κ(x)

between residue fields.

Facts & Assumptions

Given: A morphism of locally ringed spaces (f,f♯):(X,OX)→(Y,OY) and a point x∈X.

[F1]

A local ring has a unique maximal ideal, and its residue field is the quotient by that ideal (A local ring is a nonzero commutative ring with a unique maximal ideal).

[F2]

In a morphism of locally ringed spaces, the stalk map fx♯:OY,f(x)→OX,x sends the maximal ideal of the source into the maximal ideal of the target (Morphisms of locally ringed spaces).

Proof

technique · direct
1.1F1F2given

Let mf(x) and mx be the maximal ideals of the two stalks. By [F2], the composite OY,f(x)→ fx♯ OX,x⟶OX,x/mx kills mf(x), so it factors through the quotient OY,f(x)/mf(x).

2.1F1step 1.1∎

By [F1], the source and target quotients in step 1.1 are exactly the residue fields κ(f(x)) and κ(x). Therefore step 1.1 is the desired field homomorphism κ(f(x))→κ(x).

Depends on

Used by

Dependency tree · two levels

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Sources