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Local Yang–Baxter operators satisfy the Artin relations
Statement
Let be a monoidal category, let , let be a Yang–Baxter operator on , let , and let be the local operators of Local Yang–Baxter operators on tensor powers, so that is the local operator acting on the -th and -st tensor factors. Then
In the non-strict model the identities are those of the bracket-corrected local operators defined in Local Yang–Baxter operators on tensor powers.
Facts & Assumptions
Given: a monoidal category , an object , a Yang–Baxter operator on , an integer , and the local operators .
In a strict model the local operator is , and in general it is the bracket-corrected conjugate of that word; every is invertible (Local Yang–Baxter operators on tensor powers).
The Yang–Baxter operator satisfies the cubic equation (Yang–Baxter operators on an object).
Proof
Far commutativity in the strict model. Suppose first that is strict and . The endomorphisms and are tensor products of the identity with the single factor inserted at positions respectively ; these supports are disjoint because . Tensoring the two words and using functoriality of the tensor product, both and are the same tensor product of identities with two copies of at positions and (in the two possible orders of composition); hence .
The adjacent relation in the strict model. Suppose is strict and . Every tensor factor outside positions carries only identities in each of the words and , so both sides are tensored with an endomorphism of the three middle factors tensored with . On those three middle factors the two sides are and , which are equal by the cubic equation [L2]. Since tensoring equal morphisms with identities gives equal morphisms, .
The non-strict model. Let be the strong monoidal equivalence used in [L1], put , and let be its iterated tensor constraint. Transport as . Naturality and associativity coherence of the constraints give : apply to the bracket-corrected composite of [L1] and use the strong monoidal constraint at each tensor product. Thus sends each proposed Artin identity to the corresponding identity of steps 1.1 and 1.2, conjugated by the single isomorphism . Since an equivalence is faithful, the two identities hold in . Every comparison here is a morphism in .
Conclusion. Steps 1.1 and 1.2 prove the two families of identities in the strict model, and step 2.1 transports them to the bracket-corrected operators of the non-strict model. This proves the lemma. The argument is a finite computation in the tensor product and uses no choice principle.
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6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- P. Etingof, S. Gelaki, D. Nikshych, and V. Ostrik, Tensor Categories (AMS Mathematical Surveys and Monographs 205), author's final version (standard reference, not scraped)
- V. G. Turaev, Quantum Invariants of Knots and 3-Manifolds (de Gruyter Studies in Mathematics 18, 1994) (standard reference, not scraped)