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Supremum distance controls local log-Gaussian density distances

Statement

Let (X,A,ν) be a measure space, and let w,w0:X→R be measurable with finite positive normalizers Zw=∫ew dν and Z0=∫ew0 dν. Set pw=ew/Zw, p0=ew0/Z0, and r=∥w−w0∥∞≤1. With root-L2 Hellinger distance as in Root-L2 Hellinger distance between density laws, and the directional convention of Kullback–Leibler divergence, h(Pw,P0)≤err,KL(P0∥Pw)≤12e2rr2,∫(log⁡pwp0)2p0 dν≤4r2.

Facts & Assumptions

Given: The stated measurable functions, finite positive normalizers and supremum-distance bound.

[A1]

Assume AC for the imported directional KL convention The Axiom of Choice.

[F1]

Root-L2 Hellinger distance between density laws: h2(Pw,P0)=∫(pw−p0)2 dν.

[F2]

A uniform derivative bound gives a uniform Taylor remainder bound: if a scalar function has derivatives through order two on the closed interval between the two inputs, with the usual endpoint continuity, its first-order Taylor remainder is bounded by half a bound on the absolute second derivative times the squared increment.

[F3]

The mean value theorem, as the case g(x)=x of Cauchy's: for f continuous on [a,b] with a<b and differentiable on (a,b) there is c∈(a,b) with f(b)−f(a)=f′(c)(b−a): for a scalar function continuous on the closed interval between distinct inputs and differentiable on its interior, the increment equals its derivative at an intermediate point times the input increment. By The exponential function is smooth and (exp⁡)′=exp⁡, the exponential is C∞ with derivative equal to itself, so it satisfies these hypotheses on every compact interval.

[F4]

The natural logarithm has derivative 1/x and equals the integral from 1 to x of 1/t: log⁡x=∫1xdt/t for x>0; hence log⁡(1+x)≤x for x≥0.

Proof

1.1givenalgebra

Put g=w−w0, c=log⁡∫egp0 dν. Since e−r≤eg≤er, we have ∣c∣≤r and log⁡(pw/p0)=g−c, so ∣log⁡(pw/p0)∣≤2r. Squaring and integrating against the probability density p0 proves the log-square bound.

1.2A1F2F3F4givenalgebra

The directional divergence is KL(P0∥Pw)=c−∫gp0 dν=log⁡∫eg−∫gp0dνp0 dν. Let U=g−∫gp0dν. Then E0U=0, ∣U∣≤2r, and E0U2≤E0g2≤r2. Taylor's remainder [F2], applied to eu at zero, gives eU≤1+U+12e2rU2; hence E0eU≤1+12e2rr2. The integral formula in [F4] gives log⁡(1+x)≤x for x≥0, so the KL bound follows.

2.1F1F3step 1.1givenalgebra∎

Write R=pw/p0=eg−c. Then ∣R−1∣=∣e(g−c)/2−1∣≤er∣g−c∣/2≤err, by [F3]. Therefore h2(Pw,P0)=E0(R−1)2≤e2rr2, which yields the Hellinger bound.

Source notes

The cited treatments compare Hellinger, directional KL and log-likelihood variance to the supremum norm. The displayed constants here are derived directly under the finite-normalizer hypotheses.

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