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The Euclidean logarithmic norm is a real Rayleigh-quotient maximum

Statement

For n≥1 and A∈Mn(C), HA=(A+A∗)/2 is Hermitian, its eigenvalues are real, and

μ2(A)=λmax⁡(HA)=max⁡∥x∥2=1Re⁡⟨Ax,x⟩.

Facts & Assumptions

Given: n≥1, A∈Mn(C), and HA=(A+A∗)/2 as in The Euclidean logarithmic norm of a complex matrix.

[F1]

The standard formulas ⟨x,y⟩=∑k<nxkyk on Rn and ∑k<nxkyk‾ on Cn are inner products: ⟨x,y⟩=∑i<nxiyi‾ is the standard complex inner product, linear in the first variable.

[F2]

In orthonormal bases, the matrix of the adjoint is the conjugate transpose of the matrix: in orthonormal coordinates, the matrix of the adjoint is the conjugate transpose.

[F3]

Self-adjoint and normal endomorphisms of a finite-dimensional real or complex inner product space: a self-adjoint endomorphism satisfies H∗=H and is normal.

[F4]

Complex spectral theorem: a normal endomorphism of a finite-dimensional complex inner product space has an orthonormal eigenbasis, and conversely: every normal endomorphism of a finite-dimensional complex inner-product space has an orthonormal eigenbasis.

[F5]

The Euclidean logarithmic norm of a complex matrix: μ2(A)=λmax⁡(HA) for HA=(A+A∗)/2.

Proof

technique · direct
1.1givenF2F3algebra

By [F2], HA∗=(A∗+A)/2=HA, so HA is self-adjoint and hence normal by [F3].

2.1step 1.1F1F3F4choosealgebra

By [F4], choose an orthonormal eigenbasis u1,…,un for HA, with HAuj=λjuj. Since λj=⟨HAuj,uj⟩ and self-adjointness gives ⟨HAuj,uj⟩=⟨uj,HAuj⟩=⟨HAuj,uj⟩‾, each eigenvalue λj is real; the finite set has a largest member.

3.1givenstep 2.1F5

By [F5], μ2(A)=λmax⁡(HA)=max⁡jλj.

4.1step 2.1step 3.1F1F2algebra∎

For x=∑j=1ncjuj, [F1] and orthonormality give ⟨HAx,x⟩=∑jλj∣cj∣2≤μ2(A)∑j∣cj∣2=μ2(A)∥x∥22. Also ⟨HAx,x⟩=Re⁡⟨Ax,x⟩ because ⟨A∗x,x⟩=⟨Ax,x⟩‾. A unit eigenvector for the largest λj attains equality, proving the maximum formula.

Depends on

Used by

Cited to discharge well-definedness by The Euclidean logarithmic norm of a complex matrix.

Dependency tree · two levels

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Sources