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Metric properness agrees with proper discontinuity on proper discrete metric spaces
Statement
Let act isometrically on a proper discrete metric space . Then the metric-properness condition of Isometric, proper, and cobounded actions on metric spaces is equivalent to the usual proper-discontinuity condition that for every finite subset , the set is finite.
Equivalently, it is enough to require that for every and every , the set be finite.
Facts & Assumptions
Given: An isometric action of on a proper discrete metric space .
The action is proper when, for every bounded subsets , the transporter set is finite (Isometric, proper, and cobounded actions on metric spaces).
In a proper discrete metric space, bounded subsets are finite. [given]
Proof
If the action is proper in the metric sense, then [L2] turns every finite set into a bounded set. So for every finite , the set is finite by [L1].
Conversely, suppose the finite-set condition holds. Let be bounded. By [L2], the union is finite. If , then certainly , so the transporter of into is contained in the finite set supplied for . Hence the action is proper in the metric sense.
The finite-set condition implies the pointwise bound by taking ; and the pointwise bound implies the finite-set condition because a finite set lies in some ball . Thus all three formulations are equivalent.
Depends on
Used by
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Sources
- C. Löh, Geometric Group Theory, Sections 4.4 and 5.1 (standard reference, not scraped)
- C. Drutu and M. Kapovich, Lectures on Geometric Group Theory, Chapter 5 (standard reference, not scraped)