Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-26
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Metric properness agrees with proper discontinuity on proper discrete metric spaces

Statement

Let G act isometrically on a proper discrete metric space X. Then the metric-properness condition of Isometric, proper, and cobounded actions on metric spaces is equivalent to the usual proper-discontinuity condition that for every finite subset FX, the set {gG:(gF)F} is finite.

Equivalently, it is enough to require that for every xX and every R0, the set {gG:d(x, gx)R} be finite.

Facts & Assumptions

Given: An isometric action of G on a proper discrete metric space X.

[L1]

The action is proper when, for every bounded subsets B,CX, the transporter set {gG:(gB)C} is finite (Isometric, proper, and cobounded actions on metric spaces).

[L2]

In a proper discrete metric space, bounded subsets are finite. [given]

Proof

technique · direct
1.1

If the action is proper in the metric sense, then [L2] turns every finite set into a bounded set. So for every finite FX, the set {gG:(gF)F} is finite by [L1].

L1L2
1.2

Conversely, suppose the finite-set condition holds. Let B,CX be bounded. By [L2], the union F:=BC is finite. If (gB)C, then certainly (gF)F, so the transporter of B into C is contained in the finite set supplied for F. Hence the action is proper in the metric sense.

L1L2
2.1

The finite-set condition implies the pointwise bound by taking F:=Bˉ(x,R); and the pointwise bound implies the finite-set condition because a finite set lies in some ball Bˉ(x,R). Thus all three formulations are equivalent.

step 1.1step 1.2algebra

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources