How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
Multiplicative type groups split over a finite Galois extension
Statement
Assume the Axiom of Choice. Let be a separable closure of an arbitrary field . Every finite-type group of multiplicative type over is diagonalizable over , and over a finite Galois subextension of .
Facts & Assumptions
Multiplicative type has the full fpqc group-scheme convention of Groups of multiplicative type and tori. Assuming AC, Affineness of a field form of a diagonalizable group proves affineness and splitting over a field.
Assume The Axiom of Choice; its use is precisely the affine field-descent interface in F1.
Finite coalgebra pieces and their split duals are supplied by Finite coalgebra pieces of a multiplicative coordinate algebra.
Monomials are all characters, and finite algebra generation is equivalent to finite group generation: Split diagonalizable groups are dual to abelian groups.
Normal separable finite extensions are Galois: Equivalent characterizations of a finite Galois extension. The separable closure is fixed as part of the given data; this item does not construct it.
Proof
Given: AC and a finite-type group scheme of multiplicative type. By F1 write and choose a field extension splitting it.
The affineness and splitting data supplied by F1 give and the extension , so the calculation below takes place in the coordinate algebra of over the splitting field. For a finite subcoalgebra , the finite algebra is commutative (commutators vanish after the faithful extension to ) and satisfies by F2. For each , let be its minimal polynomial over . The independent powers preceding its degree stay independent under extension, so is also the minimal polynomial over . In , that polynomial is the product of the distinct linear factors associated to the coordinate values of . Thus is separable over . Choose a finite algebra generating set of , for example a vector-space basis. Over , each generator has a split squarefree minimal polynomial, whose Lagrange interpolation idempotents decompose the algebra into factors on which that generator is a scalar. Repeating with the finitely many generators decomposes into factors generated only by scalars, hence copies of . Dualizing shows that is spanned by group-like elements. Every element of belongs to a finite subcoalgebra by F2, so is spanned by its group-like elements.
Distinct group-like elements in any coalgebra are linearly independent. Otherwise take a shortest relation, write one as with the independent and all , and compare with . In the independent tensor family , the off-diagonal coefficients give for , so ; the diagonal and counit then give , contrary to distinctness. In a Hopf algebra the group-like elements form an abelian group under multiplication with inverse . Therefore their spanning and independence identify with as a Hopf algebra. F3 implies that is finitely generated.
Choose finite generators of . Their corresponding group-like elements are finite sums of tensors, so all their coefficients lie in a finite separable extension of . Enlarge it inside by adjoining all roots of the finitely many separable minimal polynomials of its generators. This gives a finite normal separable extension , which is Galois by F4. The corresponding group-like elements and their inverses define a Hopf map which becomes the isomorphism of step 2.1 after extension to . A map of vector spaces is injective and surjective if it becomes so after field extension: kernels and cokernels tensor exactly, and a nonzero vector stays nonzero. Thus the map is already an isomorphism over .
Depends on
Used by
Dependency tree · two levels
24 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- J. S. Milne, Algebraic Groups, corrected 2022 edition (standard reference, not scraped)
- SGA 3, Expose VIII, section 1, Polo–Gille edition (standard reference, not scraped)
- SGA 3, Expose X, section 1, Polo–Gille edition (standard reference, not scraped)