Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-13
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Mutual independence is inherited by subfamilies and by replacing events with complements

Statement

Every subfamily of a mutually independent finite family of events is mutually independent. Replacing any selection of its events by their complements also leaves a mutually independent family.

Facts & Assumptions

Given: A mutually independent finite family (Ai)i∈I.

[L1]

If C⊆D, then P(D∖C)=P(D)−P(C) and P(Ac)=1−P(A) (Normalization, nonnegativity, monotonicity, complements, and differences in a finite probability space).

[L2]

Mutual independence is the product identity for every nonempty subfamily (Independent events, pairwise independence, and mutual independence of a finite family).

Proof

technique · induction
1.1

With no event complemented, every intersection identity required for a subfamily is already one of the identities required for the original family.

L2base
1.2

Assume that after complementing any chosen r events, every resulting subfamily is mutually independent.

ih
2.1

Complement one further event Ai. For any intersection D of selected events other than Ai, the induction hypothesis gives P(D∩Ai)=P(D)P(Ai). Since D∩Aic=D∖(D∩Ai), [L1] gives P(D∩Aic)=P(D)(1−P(Ai))=P(D)P(Aic). Thus every subfamily remains mutually independent after r+1 replacements.

step 1.2L1L2algebra
3.1

Induction on the number of complemented events proves the assertion for every selection. The empty intersection has probability 1 and the empty product is 1.

step 1.1step 2.1discharge-induction∎

Depends on

Used by

Dependency tree · two levels

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Sources