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LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-30
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Rapidly increasing power substitutions isolate one highest x_n-term

Statement

Let k be a field, let n1, and let fk[x1,,xn] be nonzero. Then there exists an integer N>1 such that, after the substitution

xixi+xnNi(1i<n),

the transformed polynomial becomes a nonzero polynomial in xn over k[x1,,xn1] whose highest power of xn occurs in exactly one monomial term. Consequently, after multiplying by a nonzero scalar, the transformed polynomial is monic in xn.

Facts & Assumptions

Given: A field k, an integer n1, and a nonzero polynomial fk[x1,,xn].

[A1]

A polynomial has only finitely many monomials with nonzero coefficients.

Proof

technique · direct
1.1

Write f=α=(α1,,αn)cαx1α1xnαn with only finitely many nonzero coefficients. Choose N larger than every exponent αi occurring with cα0.

A1givenchoose
2.1

For each exponent vector α, define the weight w(α)=αn+α1N+α2N2++αn1Nn1. Because every αi<N, base-N expansion is unique, so distinct exponent vectors have distinct weights.

step 1.1algebra
3.1

After substituting xi+xnNi for xi, the monomial x1α1xnαn contributes the term cαxnw(α) to the highest xn-power coming from that monomial; all other terms from its binomial expansion have smaller xn-power. Let α be the exponent vector with maximal weight among those with cα0. By step 2.1 this α is unique, so cαxnw(α) is the unique highest xn-term of the transformed polynomial.

step 2.1choosealgebra
4.1

The transformed polynomial is therefore nonzero and has a unique highest xn-term with nonzero coefficient. Multiplying by the inverse of that coefficient makes it monic in xn.

step 3.1algebra

Used by

Dependency tree · 0 levels

Nothing. This result depends on no other item in the library.

Sources