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LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-30
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Rapidly increasing power substitutions isolate one highest x_n-term

Statement

Let k be a field, let n≥1, and let f∈k[x1,…,xn] be nonzero. Then there exists an integer N>1 such that, after the substitution xi⟼xi+xnNi(1≤i<n), the transformed polynomial becomes a nonzero polynomial in xn over k[x1,…,xn−1] whose highest power of xn occurs in exactly one monomial term. Consequently, after multiplying by a nonzero scalar, the transformed polynomial is monic in xn.

Facts & Assumptions

Given: A field k, an integer n≥1, and a nonzero polynomial f∈k[x1,…,xn].

[A1]

A polynomial has only finitely many monomials with nonzero coefficients.

Proof

technique · direct
1.1A1givenchoose

Write f=∑α=(α1,…,αn)cαx1α1⋯xnαn with only finitely many nonzero coefficients. Choose N larger than every exponent αi occurring with cα≠0.

2.1step 1.1algebra

For each exponent vector α, define the weight w(α)=αn+α1N+α2N2+⋯+αn−1Nn−1. Because every αi<N, base-N expansion is unique, so distinct exponent vectors have distinct weights.

3.1step 2.1choosealgebra

After substituting xi+xnNi for xi, the monomial x1α1⋯xnαn contributes the term cαxnw(α) to the highest xn-power coming from that monomial; all other terms from its binomial expansion have smaller xn-power. Let α∗ be the exponent vector with maximal weight among those with cα≠0. By step 2.1 this α∗ is unique, so cα∗xnw(α∗) is the unique highest xn-term of the transformed polynomial.

4.1step 3.1algebra∎

The transformed polynomial is therefore nonzero and has a unique highest xn-term with nonzero coefficient. Multiplying by the inverse of that coefficient makes it monic in xn.

Used by

Dependency tree · 0 levels

Nothing. This result depends on no other item in the library.

Sources