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A nonconstant locally uniform limit of univalent functions is univalent
Statement
Let be a complex domain, let be univalent for every , and suppose locally uniformly on . If is nonconstant, then is univalent.
Facts & Assumptions
Given: A complex domain , univalent maps , and locally uniform convergence to a nonconstant holomorphic limit.
A univalent map is injective (Univalent holomorphic functions).
A locally uniform limit of nowhere-zero holomorphic functions is either identically zero or nowhere zero (Hurwitz's zero-free limit theorem).
Proof
Fix . For each , define Since each is injective by [L1], the function has no zeros on . The removable singularity at is filled by , so each is holomorphic and nowhere zero on .
The functions converge locally uniformly to because locally uniformly and derivatives converge locally uniformly as well. Fact [L2] therefore makes either identically zero or nowhere zero.
Since is nonconstant, the function is not identically zero. Hence step 2.1 makes nowhere zero. If , then unless , so necessarily . As was arbitrary, is injective and therefore univalent by [L1].
Depends on
Used by
Dependency tree · two levels
4 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Matthias Weber, Complex Analysis, Theorem 5.2.6 (standard reference, not scraped)
- Walter Rudin, Real and Complex Analysis, Theorem 14.9 (standard reference, not scraped)