Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-27
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A nonreal root of a real polynomial comes with its complex conjugate

Statement

Let fR[x] and let zCR. If f(z)=0, then f(z)=0.

Facts & Assumptions

Given: A real polynomial fR[x] and a nonreal complex number z with f(z)=0.

[L1]

Complex conjugation is a field automorphism of C that fixes R pointwise (The only real-field automorphisms of C are the identity and complex conjugation).

Proof

technique · direct
1.1

By [L1], complex conjugation fixes every coefficient of f.

L1
1.2

Apply conjugation to the equality f(z)=0. Because conjugation is a field automorphism and fixes the coefficients of f, this gives 0=f(z)=f(z).

L1givenalgebra
2.1

Therefore z is also a root of f. Since zR, one has zz, so the two roots form a conjugate pair.

step 1.2algebra

Depends on

Used by

Dependency tree · two levels

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Sources