Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-28
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A normal upper-triangular matrix is diagonal

Statement

Let A=(aij)Mn(C). If A is upper triangular and normal, then A is diagonal.

Facts & Assumptions

Given: An upper-triangular matrix A=(aij)Mn(C) that is normal.

Proof

technique · direct
1.1

Because A is upper triangular, the n-th diagonal entry of AA is jnanj2=ann2, while the n-th diagonal entry of AA is inain2; [L1] makes these equal, so ain=0 for every i<n.

L1algebra
2.1

More generally, if every entry to the right of akk in row k is already zero, then the k-th diagonal entries of AA and AA are akk2 and ikaik2, so [L1] forces aik=0 for every i<k.

L1step 1.1algebra
3.1

Starting from k=n in step 1.1 and descending through k=n1,,1, step 2.1 shows that every entry above the diagonal is zero. Thus A is diagonal.

step 1.1step 2.1

Depends on

Used by

Dependency tree · two levels

4 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources