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One fixed transformation has constant-factor growth
Statement
Let be the integer fixed in One fixed-alphabet transformation doubles small gaps and let be the transformation of One fixed-alphabet Dinur transformation at this . Then there are constants , depending only on and on this fixed (and therefore fixed before any input graph is given), such that for every finite binary constraint graph over with edge records every vertex of has degree at most , and is deterministic and computable in time polynomial in the bit length of the explicit encoding of ; explicitly one may take , and , where are the constants attached to the input alphabet by Alphabet reduction controls explicit size and degree. In particular the growth factor is bounded by constants independent of , and maps edgeless inputs to the empty graph.
Facts & Assumptions
Given: Fix the alphabet and the integer of One fixed-alphabet transformation doubles small gaps, with .
For every integer and every finite binary -graph one has , and is a deterministic map from finite -graphs to finite -graphs. (One fixed-alphabet Dinur transformation)
The alphabet is finite of size with and . (One fixed-alphabet Dinur transformation)
The intermediate graph is a binary constraint graph over with at most ordinary edges, and it is edgeless whenever is edgeless. (One fixed-alphabet Dinur transformation)
The gap-amplification step at has output degree bound and blowup . (A complete uniform graph gap-amplification step)
The map is deterministic and runs in time polynomial in the bit length of the explicit encoding of , and the parameters depend only on and , never on or . (A complete uniform graph gap-amplification step)
For every finite alphabet with and every finite -graph with edge records, , where depends only on . (Alphabet reduction controls explicit size and degree)
For the same input , , where and are the length and largest gadget size attached to . (Alphabet reduction controls explicit size and degree)
Every vertex of has degree at most when the input has maximum degree at most , and is computable by a deterministic algorithm in time polynomial in the bit length of the explicit encoding of . (Alphabet reduction controls explicit size and degree)
The integer satisfies and depends only on the absolute constants , never on an input graph. (One fixed-alphabet transformation doubles small gaps)
Proof
Given: Use the fixed alphabet , the fixed integer of [F9] and the map .
By [F9] the integer lies in the transformation domain, so by [F1] and [F2] the map sends finite -graphs to finite -graphs by , with a finite alphabet of size at least two; by [F3] the graph has at most edge records and is edgeless when is edgeless, and by [F4] its degrees are at most .
Let be the constants attached to the alphabet by [F6]–[F8], and set , and . These are constants depending only on and , because do by [F4] and [F5], while do by their definition at the input alphabet .
Let be an arbitrary finite -graph with edge records. Applying [F6] with and , which is a finite -graph by [F1]–[F3], gives , the last inequality using [F3].
Applying [F7] to the same input gives , again using the edge bound of [F3].
Applying [F8] to with degree parameter , which bounds the degrees of by [F4], shows that every vertex of has degree at most .
By [F5] the first stage computes deterministically in time polynomial in the bit length of the explicit encoding of , so the explicit encoding of has polynomially bounded length; by [F8] the second stage computes deterministically in time polynomial in the bit length of that encoding. Composing the two deterministic polynomial-time algorithms exhibits a deterministic algorithm computing in time polynomial in the bit length of the explicit encoding of .
The graph was arbitrary, the constants depend only on and by step 1.2, and all three output bounds and the uniformity clause were established in steps 2.1–2.4; hence has the claimed constant-factor growth. If is edgeless, then is edgeless by [F3], and [F6] and [F7] applied with give and : the output is the empty graph and all bounds hold as .
Remarks
The constants are enormous — and are built from the least common multiple of the local gadget sizes — but they are fixed before any input is read, which is all the later iteration needs. Degree reduction, powering and alphabet reduction each blow up the graph by a constant factor once and the alphabet are frozen, and the composition of the three maps stays deterministic polynomial time because each stage's explicit output encoding has polynomial length. No choice principle is used.
Depends on
Used by
Dependency tree · two levels
17 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Irit Dinur, The PCP Theorem by Gap Amplification, §1.3 Theorem 1.5 (size clause size(G′) ≤ C·size(G)), printed pp. 4–5 (standard reference, not scraped)
- Sanjeev Arora and Boaz Barak, Computational Complexity: A Modern Approach, §18.5.1 gap amplification (Lemma 18.29) and §18.5.2 alphabet reduction (Lemma 18.30), printed pp. 370–379 (standard reference, not scraped)