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One-dimensional Weisfeiler–Leman refinement is invariant under graph isomorphism

Statement

Let G and H be finite vertex-labeled simple undirected graphs with labels in a common set, and let φ:G→H be a label-preserving graph isomorphism. At every finite round t, corresponding vertices have equal one-dimensional Weisfeiler–Leman colors: ctG(v)=ctH(φ(v)) for every v∈V(G). Consequently their graph color multisets agree at every round, so the refinement does not distinguish isomorphic graphs.

Facts & Assumptions

Given: The finite labeled graphs G,H and label-preserving isomorphism φ:G→H in the Statement. Prove the color and histogram claims.

[F1]

Label-preserving graph isomorphisms: φ is a bijection preserving labels and adjacency in both directions.

[F2]

Finite-round one-dimensional Weisfeiler–Leman color refinement: The round-t+1 color is the ordered pair of the vertex's round-t color and the multiset of round-t colors of its neighbors.

[F3]

Finite multisets as finitely supported multiplicity functions: Equality of finite multisets is equality of multiplicities at every element.

Proof

1.1givenF1F2inductionalgebra

By induction on t, ctG(v)=ctH(φ(v)) for every v∈V(G). At t=0 this is label preservation from [F1]. If it holds at t, bijectivity and adjacency preservation in [F1] give a bijection NG(v)→NH(φ(v)), and corresponding neighbors have equal round-t colors by the induction hypothesis. Thus the neighbor-color multisets agree; the center colors agree as well, so the ordered-pair update [F2] gives equality at round t+1.

2.1givenF1F3step 1.1algebra∎

The same vertex bijection therefore sends every occurrence of each round-t color in G to an occurrence of that color in H, and its inverse gives the reverse correspondence. Hence the two graph color multisets have equal multiplicities for each color by [F3]. Their round-t histograms agree for every finite t, so no round distinguishes them.

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