Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-06
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

An open convex neighbourhood is recovered from its gauge

Statement

If U⊆X is open, convex, and 0∈U, then U is absorbing and

U={x∈X:pU(x)<1}.

Facts & Assumptions

Given: An open convex U⊆X containing 0.

[F1]

The gauge is defined for absorbing sets by an infimum over positive dilates (Minkowski functional of an absorbing set).

Proof

technique · direct
1.1givenF1choose

Openness gives B(0,r)⊆U for some r>0. For any x, x∈(∥x∥/r+1)U, so U is absorbing and [F1] applies.

2.1step 1.1F1given

If x∈U, openness gives ε>0 with (1+ε)x∈U; hence pU(x)≤(1+ε)−1<1.

3.1step 1.1F1choose∎

If pU(x)<1, choose t<1 with x∈tU, say x=tu. Convexity and 0∈U imply tu∈U. Thus both inclusions hold.

Depends on

Used by

Dependency tree · two levels

16 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources